3.174 \(\int \frac{x^{11} (a+b \csc ^{-1}(c x))}{\sqrt{1-c^4 x^4}} \, dx\)

Optimal. Leaf size=401 \[ -\frac{\left (1-c^4 x^4\right )^{5/2} \left (a+b \csc ^{-1}(c x)\right )}{10 c^{12}}+\frac{\left (1-c^4 x^4\right )^{3/2} \left (a+b \csc ^{-1}(c x)\right )}{3 c^{12}}-\frac{\sqrt{1-c^4 x^4} \left (a+b \csc ^{-1}(c x)\right )}{2 c^{12}}-\frac{b \sqrt{1-c^2 x^2} \left (c^2 x^2+1\right )^{9/2}}{90 c^{13} x \sqrt{1-\frac{1}{c^2 x^2}}}+\frac{3 b \sqrt{1-c^2 x^2} \left (c^2 x^2+1\right )^{7/2}}{70 c^{13} x \sqrt{1-\frac{1}{c^2 x^2}}}-\frac{13 b \sqrt{1-c^2 x^2} \left (c^2 x^2+1\right )^{5/2}}{150 c^{13} x \sqrt{1-\frac{1}{c^2 x^2}}}+\frac{7 b \sqrt{1-c^2 x^2} \left (c^2 x^2+1\right )^{3/2}}{90 c^{13} x \sqrt{1-\frac{1}{c^2 x^2}}}-\frac{4 b \sqrt{1-c^2 x^2} \sqrt{c^2 x^2+1}}{15 c^{13} x \sqrt{1-\frac{1}{c^2 x^2}}}+\frac{4 b \sqrt{1-c^2 x^2} \tanh ^{-1}\left (\sqrt{c^2 x^2+1}\right )}{15 c^{13} x \sqrt{1-\frac{1}{c^2 x^2}}} \]

[Out]

(-4*b*Sqrt[1 - c^2*x^2]*Sqrt[1 + c^2*x^2])/(15*c^13*Sqrt[1 - 1/(c^2*x^2)]*x) + (7*b*Sqrt[1 - c^2*x^2]*(1 + c^2
*x^2)^(3/2))/(90*c^13*Sqrt[1 - 1/(c^2*x^2)]*x) - (13*b*Sqrt[1 - c^2*x^2]*(1 + c^2*x^2)^(5/2))/(150*c^13*Sqrt[1
- 1/(c^2*x^2)]*x) + (3*b*Sqrt[1 - c^2*x^2]*(1 + c^2*x^2)^(7/2))/(70*c^13*Sqrt[1 - 1/(c^2*x^2)]*x) - (b*Sqrt[1
- c^2*x^2]*(1 + c^2*x^2)^(9/2))/(90*c^13*Sqrt[1 - 1/(c^2*x^2)]*x) - (Sqrt[1 - c^4*x^4]*(a + b*ArcCsc[c*x]))/(
2*c^12) + ((1 - c^4*x^4)^(3/2)*(a + b*ArcCsc[c*x]))/(3*c^12) - ((1 - c^4*x^4)^(5/2)*(a + b*ArcCsc[c*x]))/(10*c
^12) + (4*b*Sqrt[1 - c^2*x^2]*ArcTanh[Sqrt[1 + c^2*x^2]])/(15*c^13*Sqrt[1 - 1/(c^2*x^2)]*x)

________________________________________________________________________________________

Rubi [A]  time = 2.52723, antiderivative size = 401, normalized size of antiderivative = 1., number of steps used = 16, number of rules used = 11, integrand size = 26, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.423, Rules used = {266, 43, 5247, 12, 6721, 6742, 848, 50, 63, 208, 783} \[ -\frac{\left (1-c^4 x^4\right )^{5/2} \left (a+b \csc ^{-1}(c x)\right )}{10 c^{12}}+\frac{\left (1-c^4 x^4\right )^{3/2} \left (a+b \csc ^{-1}(c x)\right )}{3 c^{12}}-\frac{\sqrt{1-c^4 x^4} \left (a+b \csc ^{-1}(c x)\right )}{2 c^{12}}-\frac{b \sqrt{1-c^2 x^2} \left (c^2 x^2+1\right )^{9/2}}{90 c^{13} x \sqrt{1-\frac{1}{c^2 x^2}}}+\frac{3 b \sqrt{1-c^2 x^2} \left (c^2 x^2+1\right )^{7/2}}{70 c^{13} x \sqrt{1-\frac{1}{c^2 x^2}}}-\frac{13 b \sqrt{1-c^2 x^2} \left (c^2 x^2+1\right )^{5/2}}{150 c^{13} x \sqrt{1-\frac{1}{c^2 x^2}}}+\frac{7 b \sqrt{1-c^2 x^2} \left (c^2 x^2+1\right )^{3/2}}{90 c^{13} x \sqrt{1-\frac{1}{c^2 x^2}}}-\frac{4 b \sqrt{1-c^2 x^2} \sqrt{c^2 x^2+1}}{15 c^{13} x \sqrt{1-\frac{1}{c^2 x^2}}}+\frac{4 b \sqrt{1-c^2 x^2} \tanh ^{-1}\left (\sqrt{c^2 x^2+1}\right )}{15 c^{13} x \sqrt{1-\frac{1}{c^2 x^2}}} \]

Antiderivative was successfully verified.

[In]

Int[(x^11*(a + b*ArcCsc[c*x]))/Sqrt[1 - c^4*x^4],x]

[Out]

(-4*b*Sqrt[1 - c^2*x^2]*Sqrt[1 + c^2*x^2])/(15*c^13*Sqrt[1 - 1/(c^2*x^2)]*x) + (7*b*Sqrt[1 - c^2*x^2]*(1 + c^2
*x^2)^(3/2))/(90*c^13*Sqrt[1 - 1/(c^2*x^2)]*x) - (13*b*Sqrt[1 - c^2*x^2]*(1 + c^2*x^2)^(5/2))/(150*c^13*Sqrt[1
- 1/(c^2*x^2)]*x) + (3*b*Sqrt[1 - c^2*x^2]*(1 + c^2*x^2)^(7/2))/(70*c^13*Sqrt[1 - 1/(c^2*x^2)]*x) - (b*Sqrt[1
- c^2*x^2]*(1 + c^2*x^2)^(9/2))/(90*c^13*Sqrt[1 - 1/(c^2*x^2)]*x) - (Sqrt[1 - c^4*x^4]*(a + b*ArcCsc[c*x]))/(
2*c^12) + ((1 - c^4*x^4)^(3/2)*(a + b*ArcCsc[c*x]))/(3*c^12) - ((1 - c^4*x^4)^(5/2)*(a + b*ArcCsc[c*x]))/(10*c
^12) + (4*b*Sqrt[1 - c^2*x^2]*ArcTanh[Sqrt[1 + c^2*x^2]])/(15*c^13*Sqrt[1 - 1/(c^2*x^2)]*x)

Rule 266

Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Dist[1/n, Subst[Int[x^(Simplify[(m + 1)/n] - 1)*(a
+ b*x)^p, x], x, x^n], x] /; FreeQ[{a, b, m, n, p}, x] && IntegerQ[Simplify[(m + 1)/n]]

Rule 43

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d
*x)^n, x], x] /; FreeQ[{a, b, c, d, n}, x] && NeQ[b*c - a*d, 0] && IGtQ[m, 0] && ( !IntegerQ[n] || (EqQ[c, 0]
&& LeQ[7*m + 4*n + 4, 0]) || LtQ[9*m + 5*(n + 1), 0] || GtQ[m + n + 2, 0])

Rule 5247

Int[((a_.) + ArcCsc[(c_.)*(x_)]*(b_.))*(u_), x_Symbol] :> With[{v = IntHide[u, x]}, Dist[a + b*ArcCsc[c*x], v,
x] + Dist[b/c, Int[SimplifyIntegrand[v/(x^2*Sqrt[1 - 1/(c^2*x^2)]), x], x], x] /; InverseFunctionFreeQ[v, x]]
/; FreeQ[{a, b, c}, x]

Rule 12

Int[(a_)*(u_), x_Symbol] :> Dist[a, Int[u, x], x] /; FreeQ[a, x] &&  !MatchQ[u, (b_)*(v_) /; FreeQ[b, x]]

Rule 6721

Int[(u_.)*((a_.) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Dist[(b^IntPart[p]*(a + b*x^n)^FracPart[p])/(x^(n*FracP
art[p])*(1 + a/(x^n*b))^FracPart[p]), Int[u*x^(n*p)*(1 + a/(x^n*b))^p, x], x] /; FreeQ[{a, b, p}, x] &&  !Inte
gerQ[p] && ILtQ[n, 0] &&  !RationalFunctionQ[u, x] && IntegerQ[p + 1/2]

Rule 6742

Int[u_, x_Symbol] :> With[{v = ExpandIntegrand[u, x]}, Int[v, x] /; SumQ[v]]

Rule 848

Int[((d_) + (e_.)*(x_))^(m_)*((f_.) + (g_.)*(x_))^(n_)*((a_) + (c_.)*(x_)^2)^(p_.), x_Symbol] :> Int[(d + e*x)
^(m + p)*(f + g*x)^n*(a/d + (c*x)/e)^p, x] /; FreeQ[{a, c, d, e, f, g, m, n}, x] && NeQ[e*f - d*g, 0] && EqQ[c
*d^2 + a*e^2, 0] && (IntegerQ[p] || (GtQ[a, 0] && GtQ[d, 0] && EqQ[m + p, 0]))

Rule 50

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[((a + b*x)^(m + 1)*(c + d*x)^n)/(b*
(m + n + 1)), x] + Dist[(n*(b*c - a*d))/(b*(m + n + 1)), Int[(a + b*x)^m*(c + d*x)^(n - 1), x], x] /; FreeQ[{a
, b, c, d}, x] && NeQ[b*c - a*d, 0] && GtQ[n, 0] && NeQ[m + n + 1, 0] &&  !(IGtQ[m, 0] && ( !IntegerQ[n] || (G
tQ[m, 0] && LtQ[m - n, 0]))) &&  !ILtQ[m + n + 2, 0] && IntLinearQ[a, b, c, d, m, n, x]

Rule 63

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> With[{p = Denominator[m]}, Dist[p/b, Sub
st[Int[x^(p*(m + 1) - 1)*(c - (a*d)/b + (d*x^p)/b)^n, x], x, (a + b*x)^(1/p)], x]] /; FreeQ[{a, b, c, d}, x] &
& NeQ[b*c - a*d, 0] && LtQ[-1, m, 0] && LeQ[-1, n, 0] && LeQ[Denominator[n], Denominator[m]] && IntLinearQ[a,
b, c, d, m, n, x]

Rule 208

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[-(a/b), 2]*ArcTanh[x/Rt[-(a/b), 2]])/a, x] /; FreeQ[{a,
b}, x] && NegQ[a/b]

Rule 783

Int[((d_) + (e_.)*(x_))^(m_)*((f_.) + (g_.)*(x_))*((a_) + (c_.)*(x_)^2)^(p_.), x_Symbol] :> Int[(d + e*x)^(m +
p)*(f + g*x)*(a/d + (c*x)/e)^p, x] /; FreeQ[{a, c, d, e, f, g, m}, x] && EqQ[c*d^2 + a*e^2, 0] && (IntegerQ[p
] || (GtQ[a, 0] && GtQ[d, 0] && EqQ[m + p, 0]))

Rubi steps

\begin{align*} \int \frac{x^{11} \left (a+b \csc ^{-1}(c x)\right )}{\sqrt{1-c^4 x^4}} \, dx &=-\frac{\sqrt{1-c^4 x^4} \left (a+b \csc ^{-1}(c x)\right )}{2 c^{12}}+\frac{\left (1-c^4 x^4\right )^{3/2} \left (a+b \csc ^{-1}(c x)\right )}{3 c^{12}}-\frac{\left (1-c^4 x^4\right )^{5/2} \left (a+b \csc ^{-1}(c x)\right )}{10 c^{12}}+\frac{b \int \frac{\sqrt{1-c^4 x^4} \left (-8-4 c^4 x^4-3 c^8 x^8\right )}{30 c^{12} \sqrt{1-\frac{1}{c^2 x^2}} x^2} \, dx}{c}\\ &=-\frac{\sqrt{1-c^4 x^4} \left (a+b \csc ^{-1}(c x)\right )}{2 c^{12}}+\frac{\left (1-c^4 x^4\right )^{3/2} \left (a+b \csc ^{-1}(c x)\right )}{3 c^{12}}-\frac{\left (1-c^4 x^4\right )^{5/2} \left (a+b \csc ^{-1}(c x)\right )}{10 c^{12}}+\frac{b \int \frac{\sqrt{1-c^4 x^4} \left (-8-4 c^4 x^4-3 c^8 x^8\right )}{\sqrt{1-\frac{1}{c^2 x^2}} x^2} \, dx}{30 c^{13}}\\ &=-\frac{\sqrt{1-c^4 x^4} \left (a+b \csc ^{-1}(c x)\right )}{2 c^{12}}+\frac{\left (1-c^4 x^4\right )^{3/2} \left (a+b \csc ^{-1}(c x)\right )}{3 c^{12}}-\frac{\left (1-c^4 x^4\right )^{5/2} \left (a+b \csc ^{-1}(c x)\right )}{10 c^{12}}+\frac{\left (b \sqrt{1-c^2 x^2}\right ) \int \frac{\sqrt{1-c^4 x^4} \left (-8-4 c^4 x^4-3 c^8 x^8\right )}{x \sqrt{1-c^2 x^2}} \, dx}{30 c^{13} \sqrt{1-\frac{1}{c^2 x^2}} x}\\ &=-\frac{\sqrt{1-c^4 x^4} \left (a+b \csc ^{-1}(c x)\right )}{2 c^{12}}+\frac{\left (1-c^4 x^4\right )^{3/2} \left (a+b \csc ^{-1}(c x)\right )}{3 c^{12}}-\frac{\left (1-c^4 x^4\right )^{5/2} \left (a+b \csc ^{-1}(c x)\right )}{10 c^{12}}-\frac{\left (b \sqrt{1-c^2 x^2}\right ) \operatorname{Subst}\left (\int \frac{\sqrt{1-c^4 x^2} \left (8+4 c^4 x^2+3 c^8 x^4\right )}{x \sqrt{1-c^2 x}} \, dx,x,x^2\right )}{60 c^{13} \sqrt{1-\frac{1}{c^2 x^2}} x}\\ &=-\frac{\sqrt{1-c^4 x^4} \left (a+b \csc ^{-1}(c x)\right )}{2 c^{12}}+\frac{\left (1-c^4 x^4\right )^{3/2} \left (a+b \csc ^{-1}(c x)\right )}{3 c^{12}}-\frac{\left (1-c^4 x^4\right )^{5/2} \left (a+b \csc ^{-1}(c x)\right )}{10 c^{12}}-\frac{\left (b \sqrt{1-c^2 x^2}\right ) \operatorname{Subst}\left (\int \left (\frac{8 \sqrt{1-c^4 x^2}}{x \sqrt{1-c^2 x}}+\frac{4 c^4 x \sqrt{1-c^4 x^2}}{\sqrt{1-c^2 x}}+\frac{3 c^8 x^3 \sqrt{1-c^4 x^2}}{\sqrt{1-c^2 x}}\right ) \, dx,x,x^2\right )}{60 c^{13} \sqrt{1-\frac{1}{c^2 x^2}} x}\\ &=-\frac{\sqrt{1-c^4 x^4} \left (a+b \csc ^{-1}(c x)\right )}{2 c^{12}}+\frac{\left (1-c^4 x^4\right )^{3/2} \left (a+b \csc ^{-1}(c x)\right )}{3 c^{12}}-\frac{\left (1-c^4 x^4\right )^{5/2} \left (a+b \csc ^{-1}(c x)\right )}{10 c^{12}}-\frac{\left (2 b \sqrt{1-c^2 x^2}\right ) \operatorname{Subst}\left (\int \frac{\sqrt{1-c^4 x^2}}{x \sqrt{1-c^2 x}} \, dx,x,x^2\right )}{15 c^{13} \sqrt{1-\frac{1}{c^2 x^2}} x}-\frac{\left (b \sqrt{1-c^2 x^2}\right ) \operatorname{Subst}\left (\int \frac{x \sqrt{1-c^4 x^2}}{\sqrt{1-c^2 x}} \, dx,x,x^2\right )}{15 c^9 \sqrt{1-\frac{1}{c^2 x^2}} x}-\frac{\left (b \sqrt{1-c^2 x^2}\right ) \operatorname{Subst}\left (\int \frac{x^3 \sqrt{1-c^4 x^2}}{\sqrt{1-c^2 x}} \, dx,x,x^2\right )}{20 c^5 \sqrt{1-\frac{1}{c^2 x^2}} x}\\ &=-\frac{\sqrt{1-c^4 x^4} \left (a+b \csc ^{-1}(c x)\right )}{2 c^{12}}+\frac{\left (1-c^4 x^4\right )^{3/2} \left (a+b \csc ^{-1}(c x)\right )}{3 c^{12}}-\frac{\left (1-c^4 x^4\right )^{5/2} \left (a+b \csc ^{-1}(c x)\right )}{10 c^{12}}-\frac{\left (2 b \sqrt{1-c^2 x^2}\right ) \operatorname{Subst}\left (\int \frac{\sqrt{1+c^2 x}}{x} \, dx,x,x^2\right )}{15 c^{13} \sqrt{1-\frac{1}{c^2 x^2}} x}-\frac{\left (b \sqrt{1-c^2 x^2}\right ) \operatorname{Subst}\left (\int x \sqrt{1+c^2 x} \, dx,x,x^2\right )}{15 c^9 \sqrt{1-\frac{1}{c^2 x^2}} x}-\frac{\left (b \sqrt{1-c^2 x^2}\right ) \operatorname{Subst}\left (\int x^3 \sqrt{1+c^2 x} \, dx,x,x^2\right )}{20 c^5 \sqrt{1-\frac{1}{c^2 x^2}} x}\\ &=-\frac{4 b \sqrt{1-c^2 x^2} \sqrt{1+c^2 x^2}}{15 c^{13} \sqrt{1-\frac{1}{c^2 x^2}} x}-\frac{\sqrt{1-c^4 x^4} \left (a+b \csc ^{-1}(c x)\right )}{2 c^{12}}+\frac{\left (1-c^4 x^4\right )^{3/2} \left (a+b \csc ^{-1}(c x)\right )}{3 c^{12}}-\frac{\left (1-c^4 x^4\right )^{5/2} \left (a+b \csc ^{-1}(c x)\right )}{10 c^{12}}-\frac{\left (2 b \sqrt{1-c^2 x^2}\right ) \operatorname{Subst}\left (\int \frac{1}{x \sqrt{1+c^2 x}} \, dx,x,x^2\right )}{15 c^{13} \sqrt{1-\frac{1}{c^2 x^2}} x}-\frac{\left (b \sqrt{1-c^2 x^2}\right ) \operatorname{Subst}\left (\int \left (-\frac{\sqrt{1+c^2 x}}{c^2}+\frac{\left (1+c^2 x\right )^{3/2}}{c^2}\right ) \, dx,x,x^2\right )}{15 c^9 \sqrt{1-\frac{1}{c^2 x^2}} x}-\frac{\left (b \sqrt{1-c^2 x^2}\right ) \operatorname{Subst}\left (\int \left (-\frac{\sqrt{1+c^2 x}}{c^6}+\frac{3 \left (1+c^2 x\right )^{3/2}}{c^6}-\frac{3 \left (1+c^2 x\right )^{5/2}}{c^6}+\frac{\left (1+c^2 x\right )^{7/2}}{c^6}\right ) \, dx,x,x^2\right )}{20 c^5 \sqrt{1-\frac{1}{c^2 x^2}} x}\\ &=-\frac{4 b \sqrt{1-c^2 x^2} \sqrt{1+c^2 x^2}}{15 c^{13} \sqrt{1-\frac{1}{c^2 x^2}} x}+\frac{7 b \sqrt{1-c^2 x^2} \left (1+c^2 x^2\right )^{3/2}}{90 c^{13} \sqrt{1-\frac{1}{c^2 x^2}} x}-\frac{13 b \sqrt{1-c^2 x^2} \left (1+c^2 x^2\right )^{5/2}}{150 c^{13} \sqrt{1-\frac{1}{c^2 x^2}} x}+\frac{3 b \sqrt{1-c^2 x^2} \left (1+c^2 x^2\right )^{7/2}}{70 c^{13} \sqrt{1-\frac{1}{c^2 x^2}} x}-\frac{b \sqrt{1-c^2 x^2} \left (1+c^2 x^2\right )^{9/2}}{90 c^{13} \sqrt{1-\frac{1}{c^2 x^2}} x}-\frac{\sqrt{1-c^4 x^4} \left (a+b \csc ^{-1}(c x)\right )}{2 c^{12}}+\frac{\left (1-c^4 x^4\right )^{3/2} \left (a+b \csc ^{-1}(c x)\right )}{3 c^{12}}-\frac{\left (1-c^4 x^4\right )^{5/2} \left (a+b \csc ^{-1}(c x)\right )}{10 c^{12}}-\frac{\left (4 b \sqrt{1-c^2 x^2}\right ) \operatorname{Subst}\left (\int \frac{1}{-\frac{1}{c^2}+\frac{x^2}{c^2}} \, dx,x,\sqrt{1+c^2 x^2}\right )}{15 c^{15} \sqrt{1-\frac{1}{c^2 x^2}} x}\\ &=-\frac{4 b \sqrt{1-c^2 x^2} \sqrt{1+c^2 x^2}}{15 c^{13} \sqrt{1-\frac{1}{c^2 x^2}} x}+\frac{7 b \sqrt{1-c^2 x^2} \left (1+c^2 x^2\right )^{3/2}}{90 c^{13} \sqrt{1-\frac{1}{c^2 x^2}} x}-\frac{13 b \sqrt{1-c^2 x^2} \left (1+c^2 x^2\right )^{5/2}}{150 c^{13} \sqrt{1-\frac{1}{c^2 x^2}} x}+\frac{3 b \sqrt{1-c^2 x^2} \left (1+c^2 x^2\right )^{7/2}}{70 c^{13} \sqrt{1-\frac{1}{c^2 x^2}} x}-\frac{b \sqrt{1-c^2 x^2} \left (1+c^2 x^2\right )^{9/2}}{90 c^{13} \sqrt{1-\frac{1}{c^2 x^2}} x}-\frac{\sqrt{1-c^4 x^4} \left (a+b \csc ^{-1}(c x)\right )}{2 c^{12}}+\frac{\left (1-c^4 x^4\right )^{3/2} \left (a+b \csc ^{-1}(c x)\right )}{3 c^{12}}-\frac{\left (1-c^4 x^4\right )^{5/2} \left (a+b \csc ^{-1}(c x)\right )}{10 c^{12}}+\frac{4 b \sqrt{1-c^2 x^2} \tanh ^{-1}\left (\sqrt{1+c^2 x^2}\right )}{15 c^{13} \sqrt{1-\frac{1}{c^2 x^2}} x}\\ \end{align*}

Mathematica [A]  time = 0.290755, size = 194, normalized size = 0.48 \[ -\frac{105 a \sqrt{1-c^4 x^4} \left (3 c^8 x^8+4 c^4 x^4+8\right )+\frac{b c x \sqrt{1-\frac{1}{c^2 x^2}} \sqrt{1-c^4 x^4} \left (35 c^8 x^8+5 c^6 x^6+78 c^4 x^4+36 c^2 x^2+768\right )}{c^2 x^2-1}+840 b \tan ^{-1}\left (\frac{c x \sqrt{1-\frac{1}{c^2 x^2}}}{\sqrt{1-c^4 x^4}}\right )+105 b \sqrt{1-c^4 x^4} \left (3 c^8 x^8+4 c^4 x^4+8\right ) \csc ^{-1}(c x)}{3150 c^{12}} \]

Antiderivative was successfully verified.

[In]

Integrate[(x^11*(a + b*ArcCsc[c*x]))/Sqrt[1 - c^4*x^4],x]

[Out]

-(105*a*Sqrt[1 - c^4*x^4]*(8 + 4*c^4*x^4 + 3*c^8*x^8) + (b*c*Sqrt[1 - 1/(c^2*x^2)]*x*Sqrt[1 - c^4*x^4]*(768 +
36*c^2*x^2 + 78*c^4*x^4 + 5*c^6*x^6 + 35*c^8*x^8))/(-1 + c^2*x^2) + 105*b*Sqrt[1 - c^4*x^4]*(8 + 4*c^4*x^4 + 3
*c^8*x^8)*ArcCsc[c*x] + 840*b*ArcTan[(c*Sqrt[1 - 1/(c^2*x^2)]*x)/Sqrt[1 - c^4*x^4]])/(3150*c^12)

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Maple [F]  time = 22.796, size = 0, normalized size = 0. \begin{align*} \int{{x}^{11} \left ( a+b{\rm arccsc} \left (cx\right ) \right ){\frac{1}{\sqrt{-{c}^{4}{x}^{4}+1}}}}\, dx \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^11*(a+b*arccsc(c*x))/(-c^4*x^4+1)^(1/2),x)

[Out]

int(x^11*(a+b*arccsc(c*x))/(-c^4*x^4+1)^(1/2),x)

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Maxima [F]  time = 0., size = 0, normalized size = 0. \begin{align*} -\frac{1}{30} \, a{\left (\frac{3 \,{\left (-c^{4} x^{4} + 1\right )}^{\frac{5}{2}}}{c^{12}} - \frac{10 \,{\left (-c^{4} x^{4} + 1\right )}^{\frac{3}{2}}}{c^{12}} + \frac{15 \, \sqrt{-c^{4} x^{4} + 1}}{c^{12}}\right )} + \frac{{\left (c^{12} \int \frac{{\left (3 \, c^{10} x^{11} + 3 \, c^{8} x^{9} + 4 \, c^{6} x^{7} + 4 \, c^{4} x^{5} + 8 \, c^{2} x^{3} + 8 \, x\right )} e^{\left (-\frac{1}{2} \, \log \left (c^{2} x^{2} + 1\right ) + \frac{1}{2} \, \log \left (c x - 1\right )\right )}}{{\left (c x + 1\right )}{\left (c x - 1\right )} \sqrt{-c x + 1} c^{10} + \sqrt{-c x + 1} c^{10}}\,{d x} -{\left (3 \, c^{8} x^{8} \arctan \left (1, \sqrt{c x + 1} \sqrt{c x - 1}\right ) + 4 \, c^{4} x^{4} \arctan \left (1, \sqrt{c x + 1} \sqrt{c x - 1}\right ) + 8 \, \arctan \left (1, \sqrt{c x + 1} \sqrt{c x - 1}\right )\right )} \sqrt{c^{2} x^{2} + 1} \sqrt{c x + 1} \sqrt{-c x + 1}\right )} b}{30 \, c^{12}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^11*(a+b*arccsc(c*x))/(-c^4*x^4+1)^(1/2),x, algorithm="maxima")

[Out]

-1/30*a*(3*(-c^4*x^4 + 1)^(5/2)/c^12 - 10*(-c^4*x^4 + 1)^(3/2)/c^12 + 15*sqrt(-c^4*x^4 + 1)/c^12) + 1/30*(30*c
^12*integrate(1/30*(3*c^10*x^11 + 3*c^8*x^9 + 4*c^6*x^7 + 4*c^4*x^5 + 8*c^2*x^3 + 8*x)*e^(-1/2*log(c^2*x^2 + 1
) + 1/2*log(c*x - 1))/(c^10*e^(log(c*x + 1) + log(c*x - 1) + 1/2*log(-c*x + 1)) + sqrt(-c*x + 1)*c^10), x) - (
3*c^8*x^8*arctan2(1, sqrt(c*x + 1)*sqrt(c*x - 1)) + 4*c^4*x^4*arctan2(1, sqrt(c*x + 1)*sqrt(c*x - 1)) + 8*arct
an2(1, sqrt(c*x + 1)*sqrt(c*x - 1)))*sqrt(c^2*x^2 + 1)*sqrt(c*x + 1)*sqrt(-c*x + 1))*b/c^12

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Fricas [F(-2)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: UnboundLocalError} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^11*(a+b*arccsc(c*x))/(-c^4*x^4+1)^(1/2),x, algorithm="fricas")

[Out]

Exception raised: UnboundLocalError

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Sympy [F(-1)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**11*(a+b*acsc(c*x))/(-c**4*x**4+1)**(1/2),x)

[Out]

Timed out

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Giac [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (b \operatorname{arccsc}\left (c x\right ) + a\right )} x^{11}}{\sqrt{-c^{4} x^{4} + 1}}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^11*(a+b*arccsc(c*x))/(-c^4*x^4+1)^(1/2),x, algorithm="giac")

[Out]

integrate((b*arccsc(c*x) + a)*x^11/sqrt(-c^4*x^4 + 1), x)